NECO 2024/2025 Physics Practical Answers

(3aix)

Table of values

E= 3.0v

[TABULATE]

S/N: 1| 2| 3| 4| 5|

L(cm): 10.0| 20.0| 30.0| 40.0| 50.0|

V(v): 2.60| 2.10| 1.90| 1.40| 1.30|

V⁻¹(v⁻¹): 0.385| 0.476| 0.588| 0.714| 0.769

(3axi)

Slope= ∆V⁻¹(v⁻¹)/∆L(cm)

Slope= (0.79 – 0.33)/(85-4)

Slope= 0.46/81

Slope= 0.00568 v⁻¹cm⁻¹

Intercept c = 0.31v⁻¹

(3axii)

K = C⁻¹

K = 1/C

K = 1/0.31

K = 3.23volts

(3axiii)

(i) I ensured tight connections

(ii) I opened the key when reading is not being taken

(3bi)

The electromotive force (EMF) of a cell represents its maximum voltage potential when not connected to a circuit, whereas the potential difference (PD) across the cell is the actual voltage measured when it’s connected to a circuit, taking into account the resistance of the circuit and the cell itself.

(3bii)

E₁ – 1.5r₁ E₂ = 1.5r

E= E₁= E₂= 1.5v

Rₜ= V/I =1.5/0.6=2.5π

¹/rₜ=¹/r₁ + ¹/r₂ = ¹/r + ¹/r => ¹/rₜ = ²/r => rₜ = ²/r

Effective circuit resistance (Rᵣ) = R + rₜ

2.5 = 2+r/2

r/2 = 2.5 – 2

r/2 = 0.5

r=2*0.5

r=1π

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